Re: Duty cycle and Even Harmonics

>- 75/25 is a 1/4 fraction, giving energy on the 1, 2, 3
>- and missing energy on the 4
<- This will give me harmonics on the 1, 2, 3, x, 5, 6, 7,
>- x, 9, … Note : 75/25 and 25/75 seems to give same
>- results, but 75/25 gives more DC current on the output,
>- a plus on a zapper.

This is a perfect example of what I am saying:

using 1.3333333 kHz as suggested, t = 750 usec.

t-high = 750 usec*0.75 = 562.50 usec freq = 1777.777/2 = 888.8885 Hz
t-low = 750 usec*0.25 = 187.50 usec freq = 5333.333/2 = 2666.666 Hz

odd, t-low is the 3rd harmonic of t-high.

t-high harmonics are 888.8885, 2666.6655, 4444.4425, 6222.2195, 7999.9965, 9777.7735, 11555.55, 13.333.327, ...

t-low harmonics are 2666.666, 7999.998, 13333.332, ...

There are NO even harmonics, only a few odd harmonics are reinforced.

66.66666666 percent duty cycle, 75 percent duty cycle, and a few others are special exceptions.

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So, what about 51 percent duty cycle ?

at 2.0 kHz, t = 500 usec


t-high = 255 usec freq = 3921.5686/2 = 1960.7843
tlow = 245 usec freq = 4081.16/2 = 2040.8163

t-high harmonics are 1960.7843, 5882.3529, 9803.9215, 13725.49, ...

t-low harmonics are 2040.8163, 6122.4489, 10204.081, 14285.714, ...

These frequencies will also beat together just as they wou with any other frequency pair and would produce as many harmonic impulses as any other set od frequencies. The point of having any special duty cycle is mute as far as this goes. As is MZap, I am seeking to find the ultimate application of zapper signals and am open to anything that will offer an improvement to the current state of art.

The production of multiple harmonics is what make the zapper as effective as it is. I am working on the practical application of these harmonics and hope to publish the information soon.

Try the same with 60:40, 79:21, 71:39, 80:20, 96:4, 93:7

In the end, you will end up with the same number of harmonics. In some cases, while the distribution may not appear as even, the peaks will be stronger.

Anyone who can disprove the above, please provide it. If you choose to do Fourier Transform, make sure that the spectral width ( resolution ) is 1 Hz or better. If you use a high enough resolution, you will see that what I am saying is true.