http://www.dnafrequencies.com/1999.shtml

"To “debilitate” this frequency, the following mathematical relationship was considered: multiplying this resonant frequency by the square root of 2 (1.4142136)."

Let us apply this to Hulda's frequencies which are resonant frequencies obtained by syncrometer method.

Multiply or divide by the square root of 2 (1.414213562373095) or √2.

This works for most of the Hulda Clark frequencies that that I have tried. It makes them several times more effective.

Newport's explanation about their distortion through filtering made me realize that those that list what organ they were found in might not work. For example, Naegleria fowleri has "(brain sec.)" written next to it. The brain tissue may have distorted the true frequency. For these who knows how well this √2 method would work. It seems to work well for big worms and flukes that were isolated on slides.

Here's an example
408000 * √2 = 576999.1334 (Ascaris lumbricoides)

If you wanted to run a diagnostic program which is what her frequencies are best used for in my opinion you could do this

#################
duty 72.5 offset - dwell 10
vbackfreq c 1.41421356 0 72.5
sweep 200000 490000 1000
##################
and then just record hits.


EDIT APRIL 28 2010- I have since realized something even better. Youll get a lower octave of what you would have gotten if you multiplied. This lower octave appears to be more effective than dividing. Both dividing and multiplying will work though because they end up being octaves of the same frequency. Try it yourself

408000 * √2 = 576999.1334 (-----multiply)
408000 / √2 = 288499.5667 (-----divide)
288499 = 576999.1334 / 2 (------ same freque, diff octave)
288499.5667 * 2 = 576999.1334 (-----see above)