Date:   3/11/2003 7:28:28 PM ( 22 y ago)
Hits:   12,036
URL:   https://www.curezone.org/forums/fm.asp?i=443465

See, here's the thing.

You assume that this is how D2SO4 works, "like H2O2 (Hydrogen-Peroxid) or O3". H2O2 (Hydrogen-Peroxid) and O3 - Ozone have an extra oxygen atom in their molecule, so they have an extra one to give up -- I don't disagree with you on that point. H2O and O2 are extremely stable, and H2O2 (Hydrogen-Peroxid) and O3 - Ozone are not terribly stable, so it makes sense that they would eventually give up their extra oxygen atom in solution to return to their more stable states. But I don't believe that D2SO4 operates this way at all. The oxygen in D2SO4 is in the sulfate ion (the SO4 part), which is fairly well bonded, as far as I know. Trying to strip an oxygen atom out of that would require a fairly enegetic reaction, I believe -- by which I mean either a complex, expensive biological reaction (rendering it pointless for our purposes) or requiring extremes of temperature (also rendering it pointless for our purposes).

So we're not talking about the same thing at all.

According to what I have read so far, deuterium sulfate acts as a catalyst to split existing water molecules in your body into H2 and O- (net result). So it isn't actually adding oxygen to your body as O3 - Ozone and H2O2 do, by giving up their extra oxygen atom, but instead it liberates a small portion of the oxygen already present in the water in your body. If this information is true (and, again, I'm still looking for the basic research, but I haven't encountered any hard evidence yet which claims that this is bunk), then the D2SO4 is actually far more effective than your H2O2 therapy, since, as a catalyst, it would liberate far more oxygen per drop than you could possibly pack into a drop of H2O2.

When I get my hands on the complete data, I'll be sure to post it.

=-John-=

 

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