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Re: If you own a constant current ionic silver generator .. by Silver_Is_Money ..... Colloidal Silver Forum

Date:   4/12/2010 7:18:10 PM ( 15 y ago)
Hits:   21,073
URL:   https://www.curezone.org/forums/fm.asp?i=1604992

I will increase the spacing to 1.5", and replace my LM334Z's ~68 ohm resistor with a resistor of ~27 ohms.

For the LM334Z this calculation is:

ISet = (227 uV * T) / RSet
Where T = the ambient temperature in degrees Kelvin.


Calculating for 70 degrees Fahrenheit ambient temperature (which is 294.11 degrees Kelvin) and a circuit with a desired 2,500 uA of current (which is 2.5 mA, or 0.0025 A) is as follows:

ISet = 0.0025 A = [(227/1,000,000) * 294.11] / RSet

Simplifying and rearranging you get:

RSet = (0.000227 * 294.11)/0.0025

RSet = 26.7 Ohms

This should hold current at a constant 2,500 uA (or 2.5 mA)
 

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